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a) The governing equation here is Power = current x voltage or P=IV. using this formula, 1,800 = I x 230 => I=1800/230 = 7.83 A (3sf) b) as watts is equal to joules/seconds, we can find the energy in j...
The key to solving this problem is realising that gravitational potential energy and elastic potential energy need to be equated. The gravitational potential energy of an object of mass m at height h abov...
We have to appreciate the assumptions we are working with. The problem states that power is available infinitely, therefore the maximum acceleration influencing factor is the tire grip. It is reached when...
The force of gravity acts on an object, causing it to accelerate towards the earth. As it’s velocity increases the drag force (friction) exerted on it by the air increases. When the two forces on the obje...
a) To begin with we will calculate the gravitational potential energy at height, h. This is the result of the mass, m, being lifted through earth's gravitational pull, (approximated as g = 9.81 m/s at the...
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