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x^3-6x^2+9x=x(x^2-6x+9)

observe binomial formula (x-3)^2=(x^2-6x+9)

Thus x(x-3)^2 and the function has two points meeting the x-axis.

First step: integrate int df/dx = x^2+3x+c (never forget the constant!) 

Second step: substitute the point in order to get c 

1 = (1)^2+3*1+c -> c = 1-1-3=-3

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