Find the derivation of (sinx)(e^2x)
Because there are two forms of x , the form uv'+vu' must be used.
If y=sinx , dy/dx=cosx
If y=e^kx , dy/dx=ke^kx
Therefore dy/dx=(sinx)(2e^2x)+(e^2x)(cosx)
EB
Because there are two forms of x , the form uv'+vu' must be used.
If y=sinx , dy/dx=cosx
If y=e^kx , dy/dx=ke^kx
Therefore dy/dx=(sinx)(2e^2x)+(e^2x)(cosx)
