curve C with parametric equations x = 4 tan(t), y=5*3^(1/2)*sin(2t). Point P lies on C with coordinates (4*3^(1/2), 15/2). Find the exact value of dy/dx at the point P.

dy/dx = dy/dt *dt/dx (chain rule).

x=4tan(t) hence dx/dt = 4 sec2(t)

y = 531/2sin(2t) hence y'= 1031/2 cos(2t)

therefore dy/dx = 1031/2 cos(2t) / 4sec2(t). Since P is on point with x=431/2 we can duduce that t=π/3 and substituting t in dy/dx we get -531/2/16

HP
Answered by Harry P. Maths tutor

8264 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

I'm supposed to calculate the differential of f(x)= sin(x)*ln(x)*(x-4)^2 using the product rule. I know what the product rule is but I can't split this into two bits that are easy to differentiate. How do I do it?


How to differentiate with respect to x, xsin2x.


A curve is given by the equation y = (1/3)x^3 -4x^2 +12x -19. Find the co-ordinates of any stationary points and determine whether they are maximum or minimun points.


How do I rationalise the denominator of a fraction which consists of surds?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning