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Solve ln(2x-3) = 1

e^ln(2x-3) = e¹
2x-3 = e
x = (e+3)/2

Answered by Jonathan C. • Maths tutor

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let p be a polynomial p(x) = x^3+bx^2+ cx+24, where b and c are integers. Find a relation between b and c knowing that (x+2) divides p(x).

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Solve ln(2x-3) = 1

Related Maths A Level answers

Differentiate: ln((e^x+1)/e^x-1))

let p be a polynomial p(x) = x^3+bx^2+ cx+24, where b and c are integers. Find a relation between b and c knowing that (x+2) divides p(x).

Find ∫ (2x^5 - 1/(4x^3)-5) dx. giving each term in its simplest form.

Integrate the function f(x) = ax^2 + bx + c over the interval [0,1], where a, b and c are constants.

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Solve ln(2x-3) = 1

Related Maths A Level answers

Differentiate: ln((e^x+1)/e^x-1))

let p be a polynomial p(x) = x^3+b*x^2+ c*x+24, where b and c are integers. Find a relation between b and c knowing that (x+2) divides p(x).

Find ∫ (2x^5 - 1/(4x^3)-5) dx. giving each term in its simplest form.

Integrate the function f(x) = ax^2 + bx + c over the interval [0,1], where a, b and c are constants.

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MyTutor is part of the IXL family of brands:

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Rosetta Stone

Wyzant

Education.com

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ABCya

© 2026 by IXL Learning

let p be a polynomial p(x) = x^3+bx^2+ cx+24, where b and c are integers. Find a relation between b and c knowing that (x+2) divides p(x).