If I throw a ball vertically upwards with a velocity of 15 m/s and we assume the gravitational acceleration is 10 m/s^2. Draw the distance-time, and velocity-time graphs, how long is the ball in the air before it returns to the point I threw it from?

We will need a SUVAT equations, so first fill in what information we have:S = 0 (the point where the ball returns to the start)U = +15 m/sV = -15 m/s (from graph)A = -10 m/s (important that this is the opposite sign to U)T = We are trying to find thisWe can use :V = U + A*Trearrange:T = (V-U)/A = (-30)/(-10) = 3 Seconds

BF
Answered by Barnaby F. Maths tutor

4110 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Particles P and Q of masses 0.4kg and m kg are joined by a light inextensible string over a smooth pulley. When released Q accelerates downward at 2.45ms^-2. Find m.


A circle C with centre at the point (2, –1) passes through the point A at (4, –5).....


Using Pythagoras' theorem, show that sin^2(x)+cos^2(x)=1 for all x.


Solve x^4+2x^2-3=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning