The curve C has the equation: y=3x^2*(x+2)^6 Find dy/dx

To find dy/dx, we must use a combination of the Product Rule and the Chain Rule.
If we let 3x^2=u and (x+2)^6=v, the Product Rule tells us that (uv)' = uv'+vu'
u'=6x, but to find v' we need to use the Chain Rule:
The Chain rule states that d/dx f(g(x)) = f'(g(x))g'(x)
(x+2)^6 can be written in the form f(g(x)) where f(x)=x^6 and g(x)=x+2, it follows that f'(x)=6x^5 and g'(x)=1
We can now see that v'=6(x+2)^5
1
Putting all this together, we find that (uv)'= 3x^26(x+2)^5 + (x+2)^66x
= 18x^2(x+2)^5 + 6x(x+2)^6

SH
Answered by Sam H. Maths tutor

3982 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is 7 to the power of 8? (


How do you differentiate (2x+xe^6x)/(9x-(2x^2)-ln(x)) w.r.t. x?


How do you integrate ln(x) with respect to x?


How exactly does integration by parts work?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning