How do I expand a bracket to a negative power if it doesn't start with a 1.

Okay so consider (2 + x)^-1, we can only do the expansion we know if the bracket starts with a 1, to fix this we can factor a 2 out of the bracket so that it becomes (2(1 + x/2))^-1. Then by our rules of powers this is the same as 2^(-1)(1 + x/2)^(-1), 2^-1 = 1/2 and we can expand the remaining bracket as we have done before, so to get the first 3 terms we'd have:1/2(1 + (-1)(x/2) + (-1)(-2)(x/2)^2/2!)= 1/2(1 - x/2 + x^2/4)= 1/2 - x/4 + x^2/8

SM
Answered by Shaun M. Maths tutor

3968 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve integral [3x^2 (x^3 + 1)^6] dx


Find the derivative of y=e^(2x)*(x^2-4x-2).


5Sin[x]-4=2Cos[2x]


If the functions f and g are defined: f: x--> x/5 + 4 g : x--> 30x + 10. what is x, if fg(x) = x. ?? What would fgf(x) = x^2 be??


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning