What's the integral of x^2 +3/x, with respect to x?

A: x³/3 + 3ln(x) + A.

Step-by-step solution:

Integral (x²+3/x dx) =

[as integrals preserve sums]

integral (x² dx) + integral (3/x dx) =

[raise exponent by one, multiply by the reciprocal, add a constant]

x³/3 + C + integral (3/x dx) =

[3 is a constant, so we we can take it out of the integral. The anti-derivative of 1/x dx is ln(x)+D, which is a standard result you need to know]

x³/3 + C + 3(ln(x) + D)=

[merge the constants into one constant]

x³/3 + 3ln(x) + A.