Solve: 3x+5y=19 4x-2y=-18

These are simultaneous equations and we need to find the value of X and Y. We can use the elimination method. The coefficients (the amount the letter is being multiplied by) of X and Y do not match. First, we need to create common coefficients to help us solve the problem. I have chosen to create the value of Ys the same. We can multiply the first equation (3x+5y=19) by 2 and the second equation (4x-2y=-18) by 5. We now have 6x+10y=38 and 20x-10y=-90. Now we can add these two new equations together to eliminate Y. This gives us 26x=-52. We can now find X by dividing both sides by 26. x=-2Now we can sub X into the first equation to find Y. Doing this gives us 3(-2)+5y=19. We now can expand the brackets to give -6+5y=19. Add 6 to both sides to get Y on its own. We now have 5y=25. Divide by 5 to get one lot of Y and we get y=5. We now know x=-2 and y=5. Finally check your answer by putting the values of X and Y in the second equation. 4(-2)-2(5)=-8-10=-18. This is correct.

CL

Related Maths GCSE answers

All answers ▸

Show that ((sqrt(18)+sqrt(2))^2)/(sqrt(8)-2) can be written in the form a(b + 2) where a and b are integers.


Solve: 3x + 4 = x + 12


Work out 2^14 ÷ (2^9)^2 in its simplest form


The width of a rectangle is X cm.
 The length is 1·5 cm more than the width.
 The perimeter of the rectangle is 17 cm. Write down an equation satisfied by X
 and solve it to find X.