5y + 1 = 3y + 13

The first step is to reverse any addition or subtraction. Gather all terms being added on one side. Remember that crossing over from one side of the equal sign to the other negates the symbol before the number so plus becomes minus and minus becomes plus. Then move the terms with y in them to the other side. Divide both sides by the constant multiplying y to get the final answer.5y = 3y +13 - 15y = 3y + 125y - 3y = 122y = 12y = 12/2y = 6

PC
Answered by Princess C. Maths tutor

4100 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

When rolling two dice, what is the probability of rolling 7?


Solve the simultaneous equations: y=x^2+4x-2, y=x+2


Expand and simplify the following; (2 + 3^0.5)^2 - (2 - 3^0.5)^2


Solve the simultaneous equations 5x+2y=13 and x-2y=5.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning