Find dy/dx when y = 5x^6 + 4x*sin(x^2)

Looking at the first element of the equation 5x6, we can simply multiply 6 by 5 to give 30 and subtract 1 from the power of x. So d/dx[5x6] = 30x5. The next element of the equation is 4xsin(x2), where we will need to use the product rule (since we have the variable x in both 4x and sin(x2) which are being multiplied) and chain rule (for sin(x2) since this is the composition of the two functions sin() and x2). From the product rule we obtain 4sin(x2) + 4xd/dx[sin(x2)]. Using the chain rule to differentiate sin(x2), we get cos(x2)d/dx[x2] = 2xcos(x2). Therefore our end result for dy/dx = 30x5 + 4sin(x2) + 4x2xcos(x2) = 30x5 + 4*sin(x2) + 8x2*cos(x2)

Answered by Mark J. Maths tutor

2038 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How is the factor theorem used?


The quadratic equation (k+1)x^2 + (5k - 3)x + 3k = 0 has equal roots. Find the possible values of k


How to draw the inverse of a function ?


What does differentiation actually mean?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy