Factorise x^2 + 3x -28

[Method 1] The solutions need to add together to make 3 and multiply to make -28. For them to multiply and make a negative number one of the solutions must also be negative and the other positive (so there are two solutions total). Things that multiply to make -28 are 4 X -7, -4 X 7, 2 X -14, -2 X 14. If we add up each of these indivudally only 7 - 4 makes 3 which is what we want for the eqaution above. We can then write the answer as (x+7)(x-4).[Method 2] Use the quadratic formula to find the solutions to this equation are -7 and 4. From there we can form the brackets by reversing the +/- and writing (x+7)(x-4).

AD
Answered by Austin D. Maths tutor

7015 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do i solve the quadratic x^2 + 5x + 6 = 0 ?


Find the roots for the quadratic equation x^(2)+6x+5=0


Solve x for (x)/(4x-1) = (6x+5)/(12x+31)


Find the coordinates of the turning point of the equation y =x^2-8x+10


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning