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Integrate exp(2x)cos(8x) by parts

Let u=exp(2x) and v'=cos(8x)From these you can obtain u' and vu=2exp(2x) and v=1/8 sin(8x)Formula: integral(uv'dx)=uv-integral(vu'dx)=1/8 exp(2x)sin(8x)-integral(1/4 sin(8x)exp(2x))=1/8exp(2x)sin(8x)+1/16...

Answered by Chloe D. • Maths tutor

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Solve the equation 8x^6 + 7x^3 -1 = 0

The first thing to recognise is this is a quadratic in disguise, therefore we can rewrite the equation in terms of a new variable y.
Where y=x³
The equation then becomes 8y²

Answered by Kelan P. • Maths tutor

7829 Views

Integrate sinxcosx dx

Since the question is a trigonometry question, we shall use integration by recognisation, in which case, we found out that the derivative of sin x is cos x.Therefore by chain rule, we can integrate the fu...

Answered by Harris L. • Maths tutor

4799 Views

How can 'for' be translated correctly in French?

When translating for in French, we have to take into consideration the three prepositions which can be used: depuis, pendant and pour. The one which is selected depends on the sit...

Answered by Lauren C. • French tutor

2301 Views