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Solve the simultaneous equations, 2x+y-5=0 and x^2-y^2=3

2x+y-5=0, y=5-2x (put into second equation)

x2-y2=3, substituting in we get, x2-(5-2x)2=3, expand, x2-(25+4x2-20x)=3, simplify, x

JS
Answered by Joshua S. Maths tutor
12400 Views

2a + 6b = 24, 3a + b = 20

a + 3b = 12, a = 12 - 3b

3(12-3b) + b = 20

36-9b + b = 20

36-8b = 20

8b = 16

b = 2

2a + 12 = 24

2a = 12

a = 6

AC
Answered by Ailsa C. Maths tutor
4174 Views

Factorise x^2 - 8x - 20

x^2 - 8x - 20

(x - 10)(x+2)

(Explanation and helping understanding) Remember the last 2 numbers must multiply to equal the last number in the question and add together to equal the middle nu...

CS
Answered by Christian S. Maths tutor
4296 Views

Expand 5(2x-6)

To begin answering this question create a small grid

put 5 on the left hand side and put 2x and -6 seperately at the top of the grid

then you can multiply 5 by 2x to gain 10x and multiply 5 ...

ZY
Answered by Zaarah Y. Maths tutor
8355 Views

How do you differentiate 5x

y=5x

The change in Y over the change in X gives the differential of 5x

As the power of 'x' is 1, this is brought down and multiplied by 5 and the power of x is 1-1 = 0. Therefore, the power ...

MM
Answered by Malik M. Maths tutor
28881 Views

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