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The line L has equation y = 5 - 2x. (a) Show that the point P (3, -1) lies on L. (b) Find an equation of the line perpendicular to L that passes through P.

(a) To confirm that point P lies on L, we must substitute x = 3 into the equation and see if we get y = -1. y = 5 - 2(3) = -1, therefore P lies on the line L (b) The gradient of the perpendicular line is ...

KS
Answered by Kitty S. Maths tutor
14282 Views

A gardener uses this formula to work out how much he charges to make a lawn. C = 7(14 +A)/ 3. C is the charge in £. A is the area in m2. He makes a rectangular lawn measuring 12.5 m by 17.6 m. How much does he charge?

Area of lawn = 12.5 x 17.6 = 220 m2 Substituting into the formula given the cost if found, C = 7(14 + 220)/3 = £546

KS
Answered by Kitty S. Maths tutor
5249 Views

How do I find f'(x) for f(x)=4x^3+x^2+5x+8?

This question require you to differentiate. The general rule for this format of differentiation is to multiply the number in front of the x by the power of the x and then reduce the power by one (in formu...

NC
Answered by Naomi C. Maths tutor
22228 Views

Differentiate f(x) with respect to x. Find the stationary value and state if it is a maxima, minima or point of inflection f(x) = 6x^3 + 2x^2 + 1

differentiate 6x^3 + 2x^2 + 1 = 18x^2 + 4x

To determine stationary point set second derivative to zero

2nd derivative =36x + 4

36x + 4 = 0 therefore x = -4/36 = -1/9

x is -ve t...

HH
Answered by Harry H. Maths tutor
3889 Views

How can you solve a quadratic equation?

There are 3 main ways of solving a quadratic equation x^2 + bx + c = 0 (we'll suppose the coefficient of x^2 is 1 for now). The first is factorisation, where if you can spot that you can factorise the exp...

WL
Answered by Warren L. Maths tutor
3753 Views

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