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expand the brackets: (x+3)(x+2)

(x+3)(x+2)we need to multiply each term by both terms in the other bracketFOIL helps us remember the process. First, Outer, Inner, Last so we don't forget any of them.Fist - in this case multiply the firs...

LW
Answered by Luke W. Maths tutor
5091 Views

Expand the following (x+4)(x+2)

The most important thing to remember when expanding brackets is to make sure that all terms in the one brackets have been multiplied with all the terms in the other.In this case we have two terms in each ...

JG
Answered by James G. Maths tutor
3854 Views

Differentiate 2e^(3x^2+6x)

Subsitute in u = 3x^2 + 6x and use chain rule to get dy/dx = dx/du x dy/dx to get dy/dx = 2(6x+6)e^(3x^2 +6)

NC
Answered by Nasser C. Maths tutor
4086 Views

Given that the binomial expansion of (1+kx)^n begins 1+8x+16x^2+... a) find k and n b) for what x is this expansion valid?

a) We compare the expansion given to the standard binomial expansion (remembering the powers of k).(1+kx)n=1+n(kx)+(n(n-1)/2)(kx)2+...As this is true for all x (for which the expansi...

GC
Answered by George C. Maths tutor
5407 Views

Given that y=(sin4x)(sec3x), use the product rule to find dy/dx

First, recall the Product rule: f(x)=g(x)*h(x), f'(x)=h(x)*g'(x)+h'(x)*g(x)This reveals the next step, to find the derivatives of our two subsidiary functions(g and h) d/dx * (sin4x) = 4cos(4x) , and d/dx...

EF
Answered by Edward F. Maths tutor
4145 Views

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