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say (2x-π/6)=qtan²q = sec²q-1so sec²q-1= 11 - sec q sec²q + sec q -12 = 0(sec q -3) (sec q + 4) = 0sec q = 3 or -4because 0<=x<= πso -π/6 <= q <= 11...

895 is approximately 90019.7 is approximately 20 900/20 = 45 it will take approximately 45 days to use all the oil in the tank

First, we gather like terms: 7x + 5x = -42 - 6 This gives: 12x = -48Now we can divide both sides by 12 to solve for x: 12x/12 = -48/12This gives: x = -4

To solve simultaneous equations we need to make either the y coefficients or the x coefficients equal so that we can cancel them out. For this set of equations we are going to make the x coefficients the ...

e^ln(2x-3) = e¹
2x-3 = e
x = (e+3)/2