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Make a the subject of 3(a+4) = ac+5f .

3a + 12 = ac + 5f 3a - ac = 5f - 12 a(3-c) = 5f - 12 a = (5f - 12)/ (3 - c)

AA
Answered by Armita A. Maths tutor
3706 Views

The line AB has equation 5x + 3y + 3 = 0 . (a) The line AB is parallel to the line with equation y = mx + 7 . Find the value of m. [2 marks] (b) The line AB intersects the line with equation 3x -2y + 17 = 0 at the point B. Find the coordinates of B.

Rearrange line into standard form.

y=5/3*x +1 

For parallel lines the gradient is the same therefore m = 5/3

Point of intersection is where two lines equal eachother

multiply o...

DH
Answered by Daniel H. Maths tutor
3832 Views

Rearrange the following to make 'W' the subject: aw + 3 = 4(bw + 5)

aw + 3 = 4(bw + 5)    Let's get rid of those brackets...
aw + 3 = 4bw + 20    Now we rearrange...
aw - 4bw = 17        Factorise...
w(a - 4b) = 17        Final rearrange...
w = 17 ...

JM
Answered by Jack M. Maths tutor
3719 Views

what is the geometrical meaning of the derivative of a function f?

The derivative of a function f(x), usually denoted as f'(x), gives you the gradient of the graph of f(x) for every point x in the domain of f. Therefoore, the derivative of a funtion can show how fast/slo...

TG
Answered by Theodore G. Maths tutor
1195 Views

How do I draw a graph, y = mx + c, if I am only given m and a point that the line passes through?

Let's say we have the equation y = 2x + c and we are told that the line passes through the point (3, 4).  Our first step is to use the numbers from the point (3, 4), by substituting them into our equation...

AD
Answered by Alex D. Maths tutor
2883 Views

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