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Use the substitution u = cos 2x to find ∫(cos^2*(2x) *sin3 (2x)) dx

∫(cos2 2x *sin3 2x)dx u = cos2x - u =(du/dx) = -2sin2x - differentiate u dx = du/(-2sin(2x)) - dx = -1/2 ∫cos22x * sin22x du - sub in dx-1/2 ∫u2(1-u<...

WB
Answered by Will B. Maths tutor
7548 Views

Does the equation x^2 + 2x + 5 = 0 have any real roots?

This equation has no real roots, as when we test the equation with the formula b2 - 4ac, we get 22 -415 = 4 - 20 = -16. As this is negative we can be assured that this equat...

SB
Answered by Sami B. Maths tutor
4893 Views

Find the gradient of the tangent and the normal to the curve f(x)= 4x^3 - 7x - 10 at the point (2, 8)

y = 4x3 - 7x -10The gradient of the function at any point can be found using its derivative:dy/dx = 12x2 - 7The gradient of the function, m1, at (2,8) is equal to the grad...

MP
Answered by Miss P. Maths tutor
5170 Views

What is compound interest?

Interest is the return you get on savings or an investment. Normal interest is when you earn a fixed percentage amount per year on an initial amount. For example an interest rate of 5% on £100 would give ...

YA
Answered by Yasmin A. Maths tutor
2855 Views

if f(x) = 4x^2 - 16ln(x-1) - 10, find f'(x) and hence solve the equation f'(x)=0.

f(x) = 4x2 - 16ln(x-1) -10, f'(x) = 8x - 16/(x-1), so if f'(x)=0, then 8x - 16/(x -1)=0, 8x(x-1) - 16 = 0, 8x2- 8x - 16 =0, 8(x2- x - 2) = 0, x2 - x - 2 = 0, (x...

EB
Answered by Ellie B. Maths tutor
3337 Views

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