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At any stationary point, the gradient of a line is zero. Therefore dy/dx = 0. If we differentiate the equation of the line, and solve this expression we can find the coordinates of the stationary po...
To integrate this function, we must first recognise that ln(x) can be treated as 1 multiplied by ln(x). Using this knowledge, we can apply the 'integration by parts method' to integrate the function.Formu...
Find the cube roots of 21/2cis(pi/4)21/2cis(pi/4+ 2pi k), for every integer k By DeMoivre:21/21/3cis((pi/4+ 2pi k)/3)321/6LRAnswered by Lisa R. • Maths tutor3503 Views
Using the chain rule, differentiate the "outside function" and the "inside function", and multiply the two results to get:dy/dx = 4(x-1)^3 * 1 = 4(x-1)^3
We know that dy/dx = (dy/dt) * (dt/dx). Differentiating each of the equations with respect to t gives. dy/dt = sec(t) tan(t) and dx/dt = sec2(t). Since dt/dx = 1 / (dx/dt) we have that dt...
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