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Differentiate and factorise y = x^2(3x + 1)

Product rule:      dy/dx = uv' + u'v dy/dx = 2x(3x + 1) + x^2(3) dy/dx = 2x(3x + 1) +3x^2 dy/dx = 6x^2 + 2x + 3x^2 dy/dx = 9x^2 + 2x dy/dx = x(9x + 2)

EJ
Answered by Ella J. Maths tutor
3433 Views

How do you prove two straight lines intersect?

There are two ways to prove they intercept (you can choose whichever one you prefer). Say we have two straight lines, for example: r1 = 3i + 4...

NM
Answered by Nicholas M. Maths tutor
10677 Views

Solve the simultaneous equations: 6x +2y = 2 and 12x - 3y = 18

6x + 2y = 2 and 12x -3y =18 

Start by multiplying the first equation by two in order to balance both equations to have equal numbers of x

12x + 4y = 4 and 12x - 3y = 18

Rearrange both...

JH
Answered by Jack H. Maths tutor
3379 Views

Given that y = x^4 tan(2x), find dy/dx

Here we have a product of two functions - they are being multiplied together - so we need to use the product rule. The product rule is: if y = u·v, dy/dx = v·u' + u·v' (where f' stands for df/dx). u = x^4...

DB
Answered by Douglas B. Maths tutor
10060 Views

Find the first four terms in the binomial expansion of (2 + x) ^5

Firstly we must take the 2 out of the bracket, as a binomial expansion must have a coefficent of 1

(2 + x)  = 2(1 + 0.5x) 5

Then, it is a good idea to qu...

FO
Answered by Fiona O. Maths tutor
18983 Views

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