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There are two points 'A' and 'B' on a graph, their coordinates are (0,1) and (10,6) respectively. 1)Find the equation of the line that runs through both of these points.2)Find the equation of a line perpendicular to this through point 'B'.

Draw a graph to see the question more clearly.1) Find the slope using the rise over run formula. ( m = 1/2 )Put this slope into the equation of a line formula along with one of the points. ( ...

RT
Answered by Robert T. Maths tutor
2787 Views

Factorise and solve x^2 -8x=15=0

x=3 or x=5

VA
Answered by Vineet A. Maths tutor
2962 Views

The straight line L1 passes through the points with coordinates (4, 6) and (12, 2) The straight line L2 passes through the origin and has gradient -3. The lines L1 and L2 intersect at point P. Find the coordinates of P.

First, find equations for the 2 lines in the standard cartesian form y=mx+c:L1: To find gradient = dy/dx = change in y/change in x = (y2-y1)/(x2-x1) = (2-6)/(12-4) = -4/8 = -0.5 = m To find intercept use ...

HF
Answered by Hugo F. Maths tutor
5138 Views

find dy/dx= x^2 +x^3

dy/dx= 2x+(1/3)x^2

SA
Answered by Safa A. Maths tutor
3474 Views

Differentiate y=3x^4 with respect to x

First we "bring the power down", that is, multiply by the power. Secondly, we subtract 1 from the power.Our answer is then dy/dx = 4*3x^(4-1) = 12x^3

EB
Answered by Ella B. Maths tutor
5103 Views

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