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Using the equation y = ax² + bx + cCreate 3 separate equations:-a(3)² + b(3) + 18 = 0 -a(-3)² + b(-3) + 18 = 0
-9a+3b = -18-9a - 3b = -18
add the equations:-9a-9...

Method 1 for solving these equations would be to multiply equation 2 (3x + 2y = 12) by 4 so that the x coefficients are equal, this becomes (12y+8x=48). Then subtract equation 1 from equation 2: (12x+8y=4...

abc = 2 x -5 x 0.5= -10 x 0.5= -20 / 2= -10
2d+10c= 2(-20) + 10(0.5)= - 40 + 5= -35

First use the gradient equation for a line: difference in y over difference in x:dy/dx = gradienttherefore: (15-9)/(d-5) = 315-9=3(d-5)6=3d-1521=3dtherefore d = 7

Call '5x + y = 21' equation 1 and 'x - 3y = 9' equation 2. To solve this, we need the coefficients of x in both equations to be the same or the coefficients of y in both equations to be the same.
Met...