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Solve the two simulatneous equations x^2+y^2=18 and x-y=3

             1) X2 +2Y2= 18 2) X - Y = 3   Rearrange 2) in the form X=3-Y then substitute in to 1); (3-y)2 +2Y2=18, this is your new equation 3 9+3Y+3Y+Y2+2Y2=18 3) 9+6y+3Y2= 18 Divide equation 3) by 3 3 ...

RC
Answered by Rebecca C. Maths tutor
5049 Views

Using methods of substitution solve the following simultaneous equations: y - 2x - 1 = 0 and 4x^2 + y^2 - 25 = 0

(1) 4x2 + y2 - 25 = 0 (2) y - 2x - 1 = 0
Rearranging (2) into an equation of y in terms of x we have:y = 2x +1
now substituting into equation (1) 4x2 + (2x +1)...

KM
Answered by Kerry M. Maths tutor
3212 Views

Solve the equation 2y^(1/2) -7y^(1/4) +3 = 0

2y1/2 -7y1/4+ 3 = 0 We need to use a substitution to obtain a quadratic.Let y1/4 = x (use the y with the smallest fractional power as your substitution)From this, we can s...

SL
Answered by Sarah L. Maths tutor
5808 Views

Using the product rule, differentiate y=(2x)(e^3x)

The product rule states that if y=uv, where u and v are both functions of x, then dy/dx = u(dv/dx) + v(du/dx)Therefore, the differential of 2xe3...

CO
Answered by Christy O. Maths tutor
5948 Views

Amanda and Wim share some money in the ratio 2:5. Wim receives £115. Calculate how much money was shared?

First, you need to find value of one part. We can see that Wim who has a share of 5 parts gets £115. So, 5 parts is equivalent to £115. Therefore, value of each part is 115/5 = £23. Now,...

SN
Answered by Saeideh N. Maths tutor
11341 Views

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