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A person swims from a depth of 0.50 m to a depth of 1.70 m below the surface of the sea. density of the sea water = 1030 kg/m^3 gravitational field strength = 9.8 N/kg Calculate the increase in pressure on the swimmer. Give the Unit.

ΔP = Δh ρ g
Δh = 1.7 - 0.5 = 1.2 m ρ = 1030 kg/m³g = 9.8 N/kg
ΔP = 1.2 (m) x 1030 (kg/m³) x 9.8 (N/kg)
= 12,112.8 N/m² = 12,112.8 Pa

Answered by Elliot P. • Physics tutor

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‘Germany was treated fairly at Versailles.’ How far do you agree with this statement? Explain your answer.

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Answered by Henry J. • History tutor

3327 Views

How do you factorise a quadratic equation?

You should already be familiar with multiplying out brackets to arrive at a quadratic equation, which will look something like the following: (x + 2)(x + 3) = x²

Answered by Eleanor M. • Maths tutor

3285 Views

When the current through an ohmic conductor is 2A, the potential difference across it is 6V. What is the potential difference across the same ohmic conductor when the current is increased to 3A?

To answer this, you need to pick up on the clues in the question. "Ohmic conductor" is explicitly mentioned twice, so this is likely to be important. You should know that for ohmic conductors, p...

Answered by Eleanor Grace G. • Physics tutor

3811 Views

How do you find the original price of a sale item when a percentage decrease has been applied?

Let's use an example, for instance, a pair a trainers in the sale are advertised as having 25% off, and are now a price of £24. How would you find the original price of the trainers before the sale?Firstl...

Answered by Eleanor Grace G. • Maths tutor

3369 Views