A particle of mass 0.8 kg moving at 4 m/s rebounds of a wall with coefficient of restitution 0.3. How much Kinetic energy is lost?
Coefficient of Restitution (CoR): Speed of Approach x CoR = Speed of Seperation 4 x 0.3 = 1.2 ms-1 Kinetic Energy (KE) Lost: KE lost = Initial KE - Final KE Initial KE = 1/2mv2 = 1/2 x 0.8 x 42 = 6.4 J Final KE = 1/2mv2 = 1/2 x 0.8 x 1.22 = 0.576 J KE lost = 6.4 - 0.576 KE lost = 5.824 J
GM
Related Maths A Level answers
All answers ▸If y=(a^(Sinx)) where a and k are given constants, find dy/dx in terms of a and x
The curve C has equation y = x^3 - 3x^2 - 9x + 14. Find the co-ordinates and nature of each of the stationery points of C.
Find the x coordinate of the minimum point of the curve y = e3x - 6e2x + 32.
How can I use the normal distribution table to find probabilities other than P(z<Z)?