Answers>Maths>A Level>Article

A particle of mass 0.8 kg moving at 4 m/s rebounds of a wall with coefficient of restitution 0.3. How much Kinetic energy is lost?

Coefficient of Restitution (CoR): Speed of Approach x CoR = Speed of Seperation 4 x 0.3 = 1.2 ms^-1 Kinetic Energy (KE) Lost: KE lost = Initial KE - Final KE Initial KE = 1/2mv² = 1/2 x 0.8 x 4² = 6.4 J Final KE = 1/2mv² = 1/2 x 0.8 x 1.2² = 0.576 J KE lost = 6.4 - 0.576 KE lost = 5.824 J

Answered by George M. • Maths tutor

4234 Views

See similar Maths A Level tutors

A particle of mass 0.8 kg moving at 4 m/s rebounds of a wall with coefficient of restitution 0.3. How much Kinetic energy is lost?

Related Maths A Level answers

Express 6cos(2x)+sin(x) in terms of sin(x). Hence solve the equation 6cos(2x) + sin(x) = 0, for 0° <= x <= 360°.

Let y = x^x. Find dy/dx.

y= arcos(x). Find dy/dx in terms of x.

differentiate with respect to x : y = x^2 -5x