Derive from the standard quadratic equation, the form of the quadratic solution

ax2+bx+c=0 : basic quadratic equation

a(x+ bx/a) + c=0  

a((x+b/2a)- b2/4a2) + c=0 (retain equation with only one x variable; compensate for b term squared out with term - b2/4a2, )

a(x+b/2a)2 - b2/4a + c= 0 (a cancels 4ato make 4a)

a(x+b/2a)2 = (b2-4ac)/4a  (rewrite b2/4a - c)

(x+b/2a)2 = (b2-4ac)/4a2

(x+b/2a) = +/-(rootof(b2-4ac))/2a  (square root gives +/- answers

x= (-b +/- (rootof(b2-4ac)))/2a  (x term singled out and the quadratic soln is written)

 

JD
Answered by Jaiveer D. Maths tutor

6751 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Using the equation cos(a+b) = cos(a)cos(b) - sin(a)sin(b) or otherwise, show that cos(2x) = 2cos^2(x) - 1.


The curve C has equation: 2x^2y + 2x + 4y – cos (piy) = 17. Use implicit differentiation to find dy/dx in terms of x and y.


I always mix up my integration and differentiation. How do i stop this?


Find the first three terms in the expansion of (4-x)^(-1/2) in ascending powers of x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning