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PQRS is a parallelogram with P->Q=a and P->S=b. Find S->Q in terms of a and b. N is a point between S and Q, where SN:NQ is 3:2, find N->R

Vectors are special in that they have a direction as well as magnitude (size).

To get from S->Q you can go from S->P = -b and then P->Q =a so S->Q = -b + a = a

Answered by Kristian B. • Maths tutor

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How can I draw a 30 degree angle without a protractor?

In the exam you will have a ruler and a pair of compasses, which you can use to construct a 60 degree angle by drawing two arcs. You can then draw two more arcs to bisect that 60 degree angle and make a 3...

Answered by Zoe C. • Maths tutor

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SOLVE THE FOLLOWING SIMULTANEOUS EQUATIONS: 5x^2 + 3x - 3y = 4, -4x - 6y + 5x^2 = -7

Question: 5x² + 3x - 3y = 4, -4x - 6y + 5x² = -7.........Step 1: make the y-coefficient equal in both equarions: (y and not x because it has the lowest power so it is easier, but x w...

Answered by Alonso M. • Maths tutor

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Use integration by parts to integrate ∫ xlnx dx

∫ u(dv/dx) dx = uv − ∫ v(du /dx)dx is the Integration by Parts formula.

If you set u=lnx, differentiation (rememeber from tables) leads to du/dx= 1/x, and dv/dx=x and so v=x^2/2 (raise power by on...

Answered by Minty M. • Maths tutor

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A circle with centre C(2, 3) passes through the point A(-4,-5). (a) Find the equation of the circle in the form (x-a)^2 + (y-b)^2=k

This question is aimed at A-Level Pure Core 1 students. A circle with centre C(2, 3) passes through the point A(-4,-5). Find the equation of the circle in the form (x-a)^2 + (y-b)^2 = k ...

Answered by Tilly C. • Maths tutor

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